Lösung.

Wir erhalten

$ \mbox{$\displaystyle \begin{array}{rcl} s_x & = & 18.5{\mbox{ (cm)}} \\ s_y... ...= & -192.5{\mbox{ (kg\,cm)}} \\ \rho_{xy} & = & -0.981\; . \\ \end{array}$}$