Lösungsvorschlag

Hier ist ein Lösungsvorschlag zur letzten Aufgabe:

#include <cstddef> /* needed for std::size_t */
#include <cstdio> /* needed for printf */
#include <cassert> /* needed for assert */

enum class StorageOrder {ColMajor, RowMajor};

struct Matrix {
   const std::size_t m; /* number of rows */
   const std::size_t n; /* number of columns */
   const std::size_t incRow;
   const std::size_t incCol;
   double* data;

   Matrix(std::size_t m, std::size_t n, StorageOrder order) :
         m(m), n(n),
         incRow(order == StorageOrder::ColMajor? 1: n),
         incCol(order == StorageOrder::RowMajor? 1: m),
         data(new double[m*n]) {
   }

   const double& operator()(std::size_t i, std::size_t j) const {
      assert(i < m && j < n);
      return data[i*incRow + j*incCol];
   }

   double& operator()(std::size_t i, std::size_t j) {
      assert(i < m && j < n);
      return data[i*incRow + j*incCol];
   }

   void init() {
      for (std::size_t i = 0; i < m; ++i) {
         for (std::size_t j = 0; j < n; ++j) {
            data[i*incRow + j*incCol] = j * n + i + 1;
         }
      }
   }

   void print() {
      for (std::size_t i = 0; i < m; ++i) {
         std::printf("  ");
         for (std::size_t j = 0; j < n; ++j) {
            std::printf(" %4.1lf", data[i*incRow + j*incCol]);
         }
         std::printf("\n");
      }
   }
};

void copy_matrix(const Matrix& A, Matrix& B) {
   /* copy A to B */
   assert(A.m == B.m && A.n == B.n);
   for (std::size_t i = 0; i < A.m; ++i) {
      for (std::size_t j = 0; j < A.n; ++j) {
         B(i, j) = A(i, j);
      }
   }
}

int main() {
   Matrix A(7, 8, StorageOrder::ColMajor);
   A.init();
   std::printf("A =\n"); A.print();
   Matrix B(7, 8, StorageOrder::RowMajor);
   copy_matrix(A, B);
   std::printf("B =\n"); B.print();
}