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Läßt sich (A) => A (für beliebiges A ∈ L) ableiten? Ja:
| P1 | = | H1(A, (A) => A) |
| = | (A) => ((A) => A) => A | |
| P2 | = | H2(A, (A) => A, A) |
| = | ((A) => ((A) => A) => A) => ((A) => (A) => A) => (A) => A | |
| P3 | = | Modus Ponens(P1, P2) |
| = | ((A) => (A) => A) => (A) => A | |
| P4 | = | H1(A, A) |
| = | (A) => (A) => A | |
| P5 | = | Modus Ponens(P4, P3) |
| = | (A) => A |
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| Copyright © 2004, 2005 Andreas Borchert, in HTML konvertiert am 18.02.2005 |